Tube-Town Forum
Technik => Tech-Talk TT-Projekte => Thema gestartet von: guibo am 5.06.2022 19:04
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I got a working px18, Bias is set around 60mV, tested working well with a 2x5.6 ohms resistance in series (20w each) and quickly tested with a testing speaker (6ohm) and a guitar.
I have got a doubt about the impedance selector, how i can measure it to find the 4 ohms and the 16 ohms selection?
I have done some measure in AC and with the speaker plugged i get:
A) 6.6 Kohms ; 10V
B) 6.2 Kohms ; 11V (middle selection so the 8ohms selection)
C) 5.5kohms, 11.25V
So which one is the 4ohms?
Thanks for your help.
regards
Antoine.
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Hi Antoine,
with the amp switched off, disconnected from mains and discharged caps:
Apply a low ac voltage (say 10V) across the primary of the output transformer (connect it to the plates of the output tubes).
If the speaker jack is a switching type that shorts to ground, insert a plug into the jack so the jack is open.
Read the ac voltage across the jack for each position of the impedance switch.
The lowest is 4 Ohms, second 8 Ohms, highest 16 Ohms.
The voltage in the 16 Ohms position should be around double the voltage in the 4 Ohms position.
Best,
Peter
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Just done it, works perfectly ! its very low voltage but i was able to read the diff, so i found the 16 ohms selection :)
Thanks you, really appreciate the tip.
regards.
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Hi,
yes, the voltage is low because of the transmission ratio of the output transformer.
But for this purpose it is perfectly fine and safer than using a higher voltage.
Best, Peter